A restaurant offers 6 choices of appetizer, 8 choices of a main meal, and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming all choices are available, how many different possible meals does the restaurant offer?

377 choices

Step-by-step explanation:

From the above question, we are told that

A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.

Let us represent each choice by :

A = Appetizer = 6

M = Main meal = 8

D = Dessert = 5

a) The combination of the 3 choices together

AMD=6 × 8 × 5=240

b) AM= Appetizer and Main meal

= 6 × 8 = 48

c) AD= Appetizer and Dessert

= 6 × 5 = 30

d) MD = Main meal × Dessert

= 8 × 5 = 40

e) A,M,D (each alone)=

Appetizer + Main meal + Dessert

= 6 + 8 + 5

= 19

Assuming all choices are available, how many different possible meals does the restaurant offer?

This is calculated as:

AMD + AM + AD + MD + A,M,D

240 + 48 + 30 + 40 + 19

= 377 choices

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answer: d.) the total number of protons and neutrons is 15

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