HELP?? A water tower is 52 feet tall and casts a shadow 78 feet long, while a child casts a shadow 6 feet long. How tall is the child?

Step-by-step explanation:

take a right triangle ABC...

right angled at B...

let AB be the height of the water tank...=52feet

AC hypotanuse...

BC is the length of the shadow..=78feet

tan thete=Opp/adj=AB/BC=52/78eq1

tan theta in both cases remain the same,

hence,

take a right triangle PQR...

right angled at Q...

let PQ be the height of the water tank...

PR hypotanuse...

QR is the length of the shadow...=6feet

tan theta=52/78 (from 1)

tan thete=Opp/adj=PQ/QR = PQ/6eq2

hence, from 1, 2

52/78=PQ/6

52x 6/78=PQ

52/13=PQ

Hence,4m=PQ=height of the boy...

Thank you, Hope this helps you dear friend

rounding to the nearest thousandth would be 452,000

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: