Find two consecutive odd whole numbers whose sum is two less than six times the first number.

Odd numbers by definition are 2k + 1

Consecutive odd numbers will be
2k + 1 and 2k + 3

Formulating the equation from the question

(2k + 1 + 2k + 3) = 6(2k+1) -2

4K + 4 = 12k + 6 -2
4= 8k + 4
K = 0

Therefore first odd number is 2k + 1 = (2 x 0) + 1 = 1

Second odd number is 2k + 3 = (2 x 0) + 3 = 3

The two numbers are 1 and 3