(HELP ASAP!) Write and solve an equation using the descriptions below.

Ten less than the quotient of a number and 3 is 6.

Seven plus the quotient of a number and 5 is -12.

Eight times the difference of a number and 3 is 40.

The difference of twice a number and 7 is 9.

Step-by-step explanation:

1) Let the number be x

Quotient of a number & 3 : x/3

Ten less than the quotient of a number : (x/3) -10

Add 10 to both sides

Multiply both sides by 3

2)  Let the number be x

Quotient of a number & 5 : x/5

Seven plus  the quotient of a number : (x/5)+7

Subtract 7 form both sides

Multiply both sides by 5

x = -19*5

x = -95

3) Let the  number be x

Difference of a number and 3 : x - 3

Eight time the difference of a  number & 3: 8*(x-3)

8*(x - 3 ) = 40

Divide both sides by 8

x - 3 = 5

Add 3 to both sides

x - 3 +3 = 5 +3

x = 8

4) Let x be the number

Twice a number : 2x

The difference of twice a number and 7: 2x - 7

2x - 7 = 9

Add 7 to both sides

2x - 7 + 7 = 9 + 7

2x = 16

Divide both sides by 2

2x/2 = 16/2

x = 8

570, the answer is 570, hope it