HELP ASAP PLEASE for the function f(x)=x^2 what effect will multiplying f(x) b y 1/4 have on the graph

Vertical Shrink of a factor of 1/4

Step-by-step explanation:

Since we are manipulating a in f(x) = a(bx - h)² + k, we are dealing with vertical stretch (x > 1) and vertical shrink (x < 1). Since 1/4 < 1, we have a vertical shrink of 1/4.

 if you multiply the f(x) by 1/4 the graph seems to narrow, which is interpreted as a positive vertical shift .  The y value (output)  is 4 times greater

If you multiply the x² by 1/4, the graph seems to widen, which is interpreted as a negative vertical shift.  The y value is less by a factor of 1/4

Step-by-step explanation:  I am reading the question literally: multiplying f(x) by 1/4.  (This may be dangerous as mathematicians have their own lingo, and some words have specialized meanings that English majors haven't learned!)

I understand that f(x) or any other function is the y-output. So in order to graph a function, it is legitimate to substitute "y" for f(x).

I am attaching a graph with the f(x)=x² in red       f(x) = (1/4)x²  in green  and  (1/4)f(x) = x²  in blue.

As you can see, very different results:  Substituting 2 for x  

in red original  4 = 2²  

in green f(x) = (1/4)(2²) .  1 = (1/4)(4)

in blue (1/4)f(x) = x²   (1/4) 16 = (2²) =.  This is probably not the intended result, but it is literally what happens if you multiply the left side!  16  is the output on the graph.

So, despite my efforts to make sense of this, I realize that this answer is mistaken, and I hope someone can clear up my confusion, please!

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph