In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the population standard deviation is 5.8 hours. Find the 98% confidence interval for the population mean. a. (17.5, 21.7)
b. (14.1, 23.2)
c. (18.3, 20.9)
d. (19.1, 20.4)

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

represent the sample mean

population mean

represent the population deviation

n=42 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

  (1)

The degrees of freedom, given by:

Since the Confidence is 0.98 or 98%, the significance would be and , and the critical value would be

Replacing we got:

And the best option for this case would be:

a. (17.5, 21.7)

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

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step-by-step explanation:

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