Mrs. Plum’s civics class is going on a field trip to observe the state legislature while it's in session. There are 24 students in the class. The gallery where the class will sit has seating for three people in the front row. In how many ways can Mrs. Plum combine three of the students to sit in the front row if the order is not important

2024 ways

Step-by-step explanation:

Because order doesn't matter in this scenario, we can use the binomial function , where n is the total number of items (students in this case) and k is the number of items we'd like to choose.

This binomial function is equivalent to:

, where n! means n * (n - 1) * (n - 2) * ... * 2 * 1

Here, we have .

Thus, the answer is 2024 ways.

~ an aesthetics lover

it would take 5 hours i think idk i'm not that good at math.can you me with my questions i need asap.

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages