To evaluate the integral 0 (t1/3 − t2/3) dt −1 , first use the property of definite integrals, that is, b (f(x) + g(x)) dx a = b f(x) dx a + b g(x) dx. a Therefore, 0 (t1/3 − t2/3) dt −1 = 0 t1/ dt −1 ---Select--- 0 t /3 dt. −1

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

the ordered pairs for the given function are of the form