Determine the slope-intercept form of the equation of the line parallel to y = -4/3 x + 11 that passes through the point (–6, 2). y = x +

-4/3x - 6

Step-by-step explanation:

First, let's find the slope of the line

y=- -4/3x+11

As the equation is already in slope-intercept form y=mx+c ,

Slope = -4/3

Let a point (x,y) be on the new line.

By finding the slope again,

y−2/x+6= -4/3

y−2= -4/3(x+6)

y−2= -4/3x−8

y = -4/3x - 6

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

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