If we transform y = x^2 by 5 units to the left and 8 units up, what is the vertex of the resulting parabola? (-5, 8)
(5,8)
(-5, -8)
(5-8)

(-5, 8)

Step-by-step explanation:

If the vertex of the parabola is on (0, 0), and moved to the left 5 units and up 8 units, the point would be (-5, 8). When a point is moved to the left, the number goes down, and when a point is moved up, it goes up in value. Therefore, you get (-5, 8).

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb