What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that apply.

y = -x - 1

Step-by-step explanation:

First, we can put the equation into y = mx + b form:

2x + 5y = 10

5y = -2x + 10

y = -x + 2

Now, we know the slope is -. A parallel line will have the same slope.

So, we can plug in the point (-5, 1) into the equation y = -x + b to find b:

1 = -(-5) + b

1 = 2 + b

-1 = b

So, the equation will be y = -x - 1

me

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)