![\left(\dfrac3{x+3}-\dfrac4{x+4}\right)\div\left(\dfrac{2x}{x+3}-\dfrac x{x+4}\right)=\\\\\\=\left(\dfrac{3(x+4)}{(x+3)(x+4)}-\dfrac{4(x+3)}{(x+4)(x+3)}\right)\div\left(\dfrac{2x(x+4)}{(x+3)(x+4)}-\dfrac{x(x+3)}{(x+4)(x+3)}\right)=\\\\\\=\dfrac{3(x+4)-4(x+3)}{(x+3)(x+4)}\div\dfrac{2x(x+4)-x(x+3)}{(x+3)(x+4)}=\\\\\\=\dfrac{3x+12-4x-12}{(x+3)(x+4)}\times\dfrac{(x+3)(x+4)}{x[2(x+4)-(x+3)]}=\\\\\\=\dfrac{-x}{(x+3)(x+4)}\times\dfrac{(x+3)(x+4)}{x(2x+8-x-3)}=\\\\\\=\dfrac{-1}1\times\dfrac1{x+5}\ =\ -\dfrac1{x+5}](/tpl/images/0705/2460/4cd09.png)
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Mathematics, 14.07.2020 09:01 decapria
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