A photo is 10 cm long. It is enlarged so that all dimensions are increased by 20%. What is the ratio of the area of the enlarged photo to the area of the original photo?

Step-by-step explanation:

Let the shape of the photo be square shaped. All the sides of a square are equal.

If the photo is 10 cm long initially, the area of the photo before enlargement will be expressed as

A1 = Length * Length

A1 = 10 * 10

A1 = 100 cm²

If the photo is enlarged so that all dimensions are increased by 20%, then increment in length = 20% of 10 cm

= 20/100 * 10

= 0.2 * 10

= 2 cm

Length of the photo after enlargement =  10 cm + 2 cm = 12 cm

Area of the enlarged photo A2 = 12 * 12 = 144 cm²

The  ratio of the area of the enlarged photo to the area of the original photo = A2/A1 = 144/100

= 72/50

= 36/25

= 1.44

a

step-by-step explanation:

the answer is a

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )