AABC has vertices at A(12, 8), B(4,8), and C(4, 14). AXYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14).

AMNO has vertices at M(4. 16), N(4.8), and O(-2.8).

AJKL has vertices at J(14, -2), K(12, 2), and L(20, 4).

are congruent. A

is a single rigid transformation that maps the two congruent triangles.

Triangle ABC and triangle XYZ

Triangle ABC and triangle MNO

Triangle JKL and triangle ABC

Triangle MNO and triangle XYZ

Triangle ABC and triangle MNO are congruent. A Rotation is a single rigid transformation that maps the two congruent triangles.

Step-by-step explanation:

ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).

ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).

Therefore:

and ΔABC ≅ ΔMNO by SSS postulate.

In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~