What are the zeroes of f(x) = x2 − 6x + 8? (4 points) x = −4, 2 x = −4, −2 x = 4, 2 x = 4, −2

Hey there! :)

Third option. x = 2, and x = 4.

Step-by-step explanation:

Find the zeros of this quadratic equation by factoring:

f(x) = x² - 6x + 8

Becomes:

f(x) = (x - 4)(x - 2)

Set each factor equal to 0 to solve for the roots;

x - 4 = 0

x = 4

x - 2 = 0

x = 2

Therefore, the zeros of this equation are at x = 2, and x = 4.

x=4  x=2

Step-by-step explanation:

f(x) = x^2 − 6x + 8

To find the zeros, set equal to zero

0  = x^2 − 6x + 8

Factor

What 2 numbers multiply to 8 and add to -6

-4*-2 = 8

-4+-2 = -6

0 = ( x-4) (x-2)

Using the zero product property

x-4 =0    x-2=0

x=4  x=2

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

umumumumum

im not sure