The total number of hamburgers sold by a national fast-food chain is growing exponentially. If 3 billion had been sold by 2003 and 9 billion had been sold by 2010, how many will have been sold by 2013

F(10) = 14.41 Billion

The total number of hamburgers that will have been sold by 2013 is 14.41 billion.

Step-by-step explanation:

The exponential function representing the total number of hamburgers sold by a national fast-food chain which grows exponentially can be expressed as;

f(t) = p(a)^t

In 2003, t = 0 and f(0) = 3 Billion

f(0) = p = 3 billion

The initial value p = 3 billion

In 2010, t = (2010-2003) = 7

f(7) = p(a)^7 = 9 billion

3(a)^7 = 9

a^7 = 9/3 = 3

a = 3^(1/7)

Therefore, the function f(t) is;

f(t) = 3(3)^(t/7) 2

In 2013, t = (2013 - 2003) = 10

Substituting t = 10 into equation 2;

f(10) = 3(3)^(10/7)

F(10) = 14.41195997001 Billion

F(10) = 14.41 Billion

The total number of hamburgers that will have been sold by 2013 is 14.41 billion.

the answer is c

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the answer is. -82562234434584

step-by-step explanation: