Write the equation of the circle The circle with center C(-2,5) and containing the point P(-2, -1)

(x+2) ^2 + (y-5)^2 = 36

Step-by-step explanation:

The equation of a circle can be written as

(x-h) ^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

The radius would be from 5 to -1 = 6 units

(x--2) ^2 + (y-5)^2 = 6^2

(x+2) ^2 + (y-5)^2 = 36

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: