Find the coefficient of fourth term of (-x -3)^5

-270

Step-by-step explanation:

Here, we want to know the coefficient of the fourth term.

The coefficients according to pascal triangle for the expansion is 1 5 10 10 5 1

So the expansion looks as follows;

1[(-x)^5(-3)^0] + 5[(-x)^4(-3)^1)] + 10[(-x)^3(-3)^2) + 10[(-x)^2(-3)^3] +

So the fourth term we are dealing with is

10[(-x)^2(-3)^3)]

So the value here is

10 * x^2 * -27

= -270 x^2

So the coefficient is -270

answer: 7270

step-by-step explanation:

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional