Line A B has a negative slope and goes through points (negative m, p) and (w, z). Line A prime B prime has a positive slope and intersects with line A B. Which coordinate for points A' and B' would help prove that lines AB and A'B' are perpendicular? A': (p, m) and B': (z, w) A': (p, m) and B': (z, −w) A': (p, −m) and B': (z, w) A': (p, −m) and B': (z, −w)

(B)A': (p, m) and B': (z, −w)

Step-by-step explanation:

Line AB has a negative slope and goes through points (-m, p) and (w, z).

Line A'B' has a positive slope and intersects with line AB.

Definition: Two lines are perpendicular if the product of their slopes is -1.

Slope of AB

From the options, we consider the coordinates whole slope multiplied by the slope of AB gives a result of -1.

In Option B: A': (p, m) and B': (z, −w)

Slope of A'B'

The product of the slopes

Therefore, the coordinate for points A' and B' which would help prove that lines AB and A'B' are perpendicular is A': (p, m) and B': (z, −w).

You can try to calculate the slope of the others. They would not satisfy this condition.

answer: hi

step-by-step explanation:

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1