A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Five marbles are drawn from the bag.
What is the approximate probability that exactly two of the five are blue?
196
496
36%
O 40%

34.56%

Approximately 35%

Step-by-step explanation:

Total number of marbles present= 10 red+ 15 yellow+5 green+20 blue

Total= 50 marbles

Probability of picking a blue ball = 20/50

Probability of a blue = 0.4= p

Probability of no blue = 1-0.4 = 0.6= q

If five balls are selected, probability of

exactly 2 to be blue is

Probability= 5C2(0.4)²(0.6)³

probability= 5!/(2!3!)(0.4)²(0.6)³

probability= 10*0.16*0.216

Probability= 0.3456

Then to percentage

0.3456 to percentage= 0.3456*100

0.3456 to percentage= 34.56%

Approximately 35%

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

only 10/60 isn't equivalent

hope this : )