PL HELP! Find all real zeros and complex of each solution x^3-5x^2+7x-35=0. SHOW WORK!!!

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x = 5, x = -i√7, x = i√7

Step-by-step explanation:

We can factor the equation x³ - 5x² + 7x - 35 = 0 by grouping:

x²(x - 5) + 7(x -5) = 0

We get:

(x² + 7)(x - 5) = 0

or

(x + i√7)(x - i√7)(x - 5) = 0

Use the Zero Product Property to solve for the solutions:

x - 5 = 0

x = 5.

x² + 7 = 0

x² = -7 (We will have imaginary solutions in this instance)

x = ±i√7

Therefore, the zeros of this equation are:

x = 5, x = -i√7, x = i√7

1 and 2

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.