In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 exams that are worth 100 points each. A student has received homework scores of 7, 8, 7, 5, and 8 and the first two exam scores are 81 and 80. Assuming that grades are assigned according to the standard scale, where if the grade percentage is 0.9 or higher the student will get an A, and if the grade percentage is between 0.8 and 0.9 the student will get a B, and there are no weights assigned to any of the grades, is it possible for the student to receive an A in the class? What is the minimum score on the third exam that will give an A? What about a B? [8 marks]

i) it is not possible for the student to receive an A in the class

ii) 119 points

iii) 84points

Step-by-step explanation:

Total exam scores = 350points

homework scores of 7, 8, 7, 5, and 8

Let the third exam score =y

Exam scores = 81, 80, x

i) To know if the student would get an A in class, we would find the third exam score

(Scores received by a student)/ (total scores) = least of the grade percentage to get an A

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.9

(196+x)/350 = 0.9

196+x = 350 × 0.9

196+x = 315

x = 315-196

x = 119

119 > 100

Since the maximum grade for each of the exam score is 100points, it is not possible for the student to receive an A in the class.

ii) Since the least of the grade percentage that would guarantee an A is 0.9, the minimum score on the third exam that will give an A = 119points

iii) (Scores received by a student)/ (total scores) = least of the grade percentage to get a B

(7 + 8 + 7 +5 + 8 + 81 + 80 + x)/350 = 0.8

(196+x)/350 = 0.8

196+x = 350 × 0.8 = 280

x = 280-196

x = 84

The minimum score on the third exam that will give a B = 84points

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.