A truck is to be filled with packages that weigh 5.8kg. If the maximum capacity of the truck is 48000 grams and there is a 5500 gram package already on the truck how many 5.8kg packages can be loaded?

7 packages

Step-by-step explanation:

From the question, we are told that a truck is to be filled with packages that weigh 5.8kg. The maximum capacity of the truck is 48000 grams(48kg) and there is a 5500 gram(5.5kg) package already in the truck.

First, we need to subtract 5.5kg from 48kg to know the amount of space left. This will be:

= 48kg - 5.5kg

= 42.5kg

To get the number of 5.8kg packages that can be loaded, we divide 42.5kg by 5.8kg. This will be:

= 42.5kg/5.8kg

= 7.3

= 7 approximately

Therefore, 7 packages will be loaded.

N.B: 1000 grams = 1 kilogram

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

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