How much of 30% HCI and 45% HCI would be needed to mix and produce 50 liters of 35% HCI

Step-by-step explanation:

Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...

  0.45x +0.30(50 -x) = 0.35(50)

  0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)

  x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl

33  1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.

Comment on the solution

You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...

  (mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3

answer: 34rtyj,jkhtyetwrhyjeuiejnbhdfknbkguxfrbhkfdbjvkmbd,kvbsd.kxjvbhjnfbgjxdfn

step-by-step explanation:

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1