Let (3, -2) be a point on the terminal side of 0. Find the exact values of sin , seco, and tan 0.

sinθ = -0.554

tanθ = -0.667

secθ = 1.203

Step-by-step explanation:

Consider the point (3, -2)

The value of x is positive and the value of y is negative.

It means the the terminal sides of angle lies in 4rth quadrant, such that:

Base = 3

Perpendicular = 2

Hypotenuse² = 2² + 3²

Hypotenuse =  3.61

sinθ = Perpendicular /Hypotenuse

sinθ = 2/3.61

As sine is negative in 4rth quadrant

sinθ = - (2/3.61)

sinθ = -0.554

tanθ = Perpendicular/ Base

tanθ = 2/3

tanθ = 0.667

As tan is negative in 4rth quadrant

tanθ = -0.667

secθ = Hypotenuse/Base

secθ = 3.61/3

secθ = 1.203

secant is positive in 4rth quadrant

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

just pick what you think i need more time let me know if this

step-by-step explanation: