The perimeter of a triangle is 82 feet. One side of the triangle is 2 times the second side. The third side is 2 feet longer than the second side. Find the length of each side.

first side=40

second side=20

third side=22

Step-by-step explanation:

LET THE SIDES OF THE TRIANGLES BE y

Perimeter=82

first side=2 x y = 2y

second side=y

third side=2 +y

2y + y + 2 + y=82

4y+2=82

4y= 82-2

4y=80

y=80/4

y=20

first side=2y=2(20)=40

second side=y=20

third side= 2 + y= 2 + 20 = 22

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

the correct answer is $7.38

step-by-step explanation: