In the following APs, find the missing terms in the boxes 1). 5_,_,9/2
2).-4,_,_,_,_,6
3)._,38,_,_,_,-22

see explanation

Step-by-step explanation:

The n th term of an AP is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

(1)

Given a₁ = 5 and a₄ = , then

5 + 3d = ( subtract 5 from both sides )

3d = - ( divide both sides by 3 )

d = -

add - to each term

5,  ,  ,  

(2)

Given a₁ = - 4 and a₆ = 6, then

- 4 + 5d = 6 ( add 4 to both sides )

5d = 10 ( divide both sides by 5 )

d = 2

Add 2 to each term

- 4,  -2,  0,  2,  4,  6

(3)

Given a₂ = 38 and a₆ = - 22, then

a₁ + d = 38 → (1)

a₁ + 5d = - 22 → (2)

Subtract (1) from (2) term by term

4d = - 60 ( divide both sides by 4 )

d = - 15

Substitute d = - 15 into (1)

a₁ - 15  = 38 ( add 15 to both sides )

a₁ = 53

Thus

53,  38,  8,  - 7,  - 22

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

i think it will be 4feet long of what i comprehend