A man reared cows and buffaloes. The number of buffaloes was 7 more than one-Third of the number of cows. What was the total number of animals, if the number of buffaloes was 21?

Step-by-step explanation:

Let the number of buffaloes be b

Let the number of cows be c

The number of buffaloes was 7 more than one-Third of the number of cows is written as

b = 7 + 1/3c

But the number of buffaloes was 21

So the number of cows are

21 = 7 + 1/3c

Multiply through by 3

63 = 21 + c

c = 63 - 21

c = 42

The number of cows is 42

So the total number of animals in the farm is

21 + 42

Hope this helps you

i do not know the answer

step-by-step explanation:

step-by-step explanation:

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