Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smaller number. Let x represent the smaller number and y represent the larger number. Which equations represent this situation? y = negative four-thirds x + 31. y = 2 x + 7. y = negative four-thirds x + StartFraction 31 Over 3 EndFraction. Y = 2 x + 7. y = negative four-thirds x + 31. y = negative 2 x + 7. y = negative four-thirds x + StartFraction 31 Over 3 EndFraction. Y = negative 2 x + 7.

Let x represent the smaller number and y represent the larger number

For the first equation

Four times a number added to 3 times a larger number is 31 is written as

4x + 3y = 31

Making y the subject we have

3y = - 4x + 31

Divide both sides by 3

That's

For the second equation

Seven subtracted from the larger number is equal to twice the smaller number is written as

y - 7 = 2x

Making y the subject

We have

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answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

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