The sum of two numbers is 21. the second number is six times the first number work out the two numbers

3 and 18

Step-by-step explanation:

hello

let note a and b the two numbers

a + b = 21

b = 6a

so 7a=21 <=> a = 3

and b = 18

hope this helps

Solution,

X + y = 21 --> equation (i)

X = 6y ( given)

According to Question,

6y + y = 21

Collect like terms

7y = 21

divide both sides of the equation by 7

7y/7 = 21/7

calculate

y = 3

Again,

Replacing value,

X = 6y

= 6 * 3

= 18

Therefore, the two numbers are 3 and 18

Hope this helps...

Good luck on your assignment

what's that

a

explanation: