What is the surface area of a cone that has a radius of 5 units and a height of 10 units? Use 3.14 for π and round your answer to the nearest whole number. 254 units2 300 units2 314 units2 384 units2

Surface area of a cone = 254 unit² (Approx)

Step-by-step explanation:

Given:

Radius(r)=  5 unit

Height(h) = 10 unit

Find:

Surface area of a cone

Computation:

Surface area of a cone = πr(r + √h²+r²)

Surface area of a cone = (3.14)(5)(5 + √10²+5²)

Surface area of a cone = 15.7(5 + √100+25)

Surface area of a cone = 15.7(5 + √125)

Surface area of a cone = 15.7(5 + 11.18)

Surface area of a cone = 15.7(16.18)

Surface area of a cone = 254.026

Surface area of a cone = 254 unit² (Approx)

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.