Tickets to a dance cost $6.50 in advance. Tickets at the door cost $8.00. A group spent $177.50 on tickets. They bought ten tickets at the door. Write an equation to describe this situation and solve it to find the number of tickets bought in advance by the group. Include statements defining the variable(s) and a concluding statement.

Number of Advance ticket = 15

Step-by-step explanation:

Given:

Advance ticket cost = $6.50

Door ticket cost = $8.00

Number of door ticket = 10

Total amount spend = $177.50

Assume:

Number of Advance ticket = x

So,

Total amount spend = [(Advance ticket cost)(Number of Advance ticket) + (Door ticket cost)(Number of door ticket)

$177.50 = [($6.5)(x) + ($8)(10)]

$177.50 = $6.5 x + $80

$97.50 = $6.5 x

x = 15

So,

Number of Advance ticket = 15

step by step explanation: when u removing the parentheses and combined them that would be : x+3y-x-y=2y

my dear correct answer is option number 3