Which sequence of transformations could be used to map triangle MNO onto M"N"O"? T(–2, 4) ry-axis ry-axisT(–2, 4) T(2, –4) T(2, –4)

(A)T(–2, 4) ry-axis

Step-by-step explanation:

The graph showing triangles MNO and M"N"O" is attached below.

From the graph, the coordinates are:

M(5,-4),N(3,-2) and O(1,-3)M"(-3,0), N"(-1,2) and O"(1,1)

When we transform triangle MNO by (-2,4), we obtain:

M'(3,0), N'(1,2) and O'(-1,1)

Next, we reflect M'N'O' the y-axis.

Note: When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite.

Therefore:

Reflection of  M'N'O' accross the y-axis gives: M"(-3,0), N"(-1,2) and O"(1,1).

Therefore, the sequence of transformations could be used to map triangle MNO onto M"N"O" is T(–2, 4) ry-axis.

The correct option is A.

In the first triangle 80+20+p=180 (since sum of all angles of a triangle is 180)so p= 80also in second triangle 55+45+q=180 (since sum of all angles of a triangle is 180)so q=80so we can conclude that p=80 degrees q=80 degrees so p=q=80 degreeshence option b is correct

The answer would be b