If a and b are rational numbers and 6/(3√2-2√3 ) = a √2-b √3 , then find the values of a and b.

=3–√−13–√+1⋅3–√−13–√−1

=(3–√−1)23–√2−12

=3–√2+12−23–√3−1

=4−23–√2

2−13–√

a=2,b=−1.

Step-by-step explanation:

step-by-step explanation:

0

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it