Pwease help fast this is mah last question! The area of the trapezium ABCD as shown in the figure (in square units) is
A) 222
B) 111
C) 224
D) 116

A  = 222 units^2

Step-by-step explanation:

To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB  (Call this point E).  Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units.  Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:

(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.

The area of this trapezoid is

A = (average vertical length)(width), which here is:

       (21 + 16) units

A  = * (12 units),   which simplifies to:

                  2

A = (37/2 units)(12 units)  =  A  = 37*6 units  =  A  = 222 units^2