In the diagram shown, FJ bisects AD BL~=LC. The length of BL is 10 less than the length of AB. The length of AD is 220. What is the length of BD?

Option (C)

Step-by-step explanation:

Since FJ is the bisector of AD,

AL ≅ DL

And it's given that BL ≅ LC

Length of BL is 10 less than the length of AB.

m(BL) = m(AB) - 10

m(AD) = 220 [Since m(AD) = 2m(AL)]

2m(AL) = 220

m(AL) = 110

m(AB) + m(BL) = 110

m(AB) + [m(AB) - 10] = 110

2m(AB) = 110 + 10

m(AB) = 60

Therefore, m(BL) = m(AL) - m(AB)

                            = 110 - 60

                            = 50

Since, m(AL) = m(DL)

m(AB) + m(BL) = m(LC) + m(CD) [Since BL = LC]

m(AB) = m(CD) = 60

Now m(BD) = m(BL) + m(LC) + m(CD)

                   = 50 + 50 + 60

                   = 160

Therefore, option (C) will be the answer.

452,489 to the nearest thousand is 452,000

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.