Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimeters and an unknown population mean. A random sample of 15 saplings is taken and gives a sample mean of 308 millimeters. Find the confidence interval for the population mean with a 90% confidence level.

The 90% confidence interval for the population mean is (300.78, 315.22).

Step-by-step explanation:

We have to calculate a 90% confidence interval for the mean.

The population standard deviation is know and is σ=17.

The sample mean is M=308.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

The z-value for a 90% confidence interval is z=1.645.

The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 90% confidence interval for the population mean is (300.78, 315.22).

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

19

step-by-step explanation: