ABCD is a quadrilateral inscribed in a circle, as shown below: Circle O is shown with a quadrilateral ABCD inscribed inside it. Angle A is labeled x plus 16. Angle B is labeled x degrees. Angle C is labeled 6x minus 4. Angle D is labeled 2x plus 16.

What equation can be used to solve for angle B?

(x + 16) − (6x − 4) = 180
(x + 16) + (x) = 90
(2x + 16) + (x) = 180
(x + 16) − (x) = 90

C. (2x + 16) + (x) = 180°

Step-by-step explanation:

See attachment for the cyclic quadrilateral

One theorem of cyclic quadrilateral states that; opposite angles = 180°

In the attachment, the angle opposite B is D

Where B = x

D = 2x + 16

From the theorem stated above;

B + D = 180°

Substitute the values of B and D in the formula above

x + 2x + 16 = 180

From the list of given options, the correct answer is C

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation: