Many manufacturing problems involve the matching of machine parts, such as shafts that fit into a value hole. A particular design requires a shaft with a diameter of 22,000 mm, but shafts with diameters between 21,990 mm and 22,010 mm are acceptable. Suppose that the manufacturing process yields shafts with diameters normally distributed with a mean of 22,002 mm and a standard deviation so 0.005 mm. For this process what is the proportion of shafts with a diameter between 22.99 mm and 22.00 mm

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

2: 10

step-by-step explanation:

ƒ = 0.03b

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step-by-step explanation: