Find the confidence interval specified. Assume that the population is normally distributed. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 206 milligrams with s = 12.7 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs.

206 ± 8.069

Step-by-step explanation: Since the confidence interval is 95%, α = 0.025.

mean = 206

s = 12.7

standard error (SE) =

SE = 3.66

The population is small, so use t-score. To do so, the degrees of freedom is:

n - 1 = 11

α = 0.025

Looking the t-score table for line 11 and column 0.025:

t-score = 2.201

Confidence interval will be:

mean ± t*SE

206 ± 2.201*3.66

206 ± 8.069

The confidence interval for the true mean is 206 ± 8.069

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;

y-1700=200(x+4)

step-by-step explanation:

200(x+4) is 200x + 800 she is saving 200 per week x is the weeks and the -1700 is. us that’s howmuch she already had