Mathematics, 18.07.2020 21:01 asimms8504

ANSWER FAST please help me answer these following question A sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Oregon are: $295, $475, $345, $595, $538, $460. A second sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Washington are $495, $422, $370, $333, $370, $390. Using the Text Editor, answer the following questions: What is the median price of rent for the University of Oregon? What is the median price of rent for the University of Washington? What is the mean price of rent near the University of Oregon? What is the mean price of rent near the University of Washington? Describe the standard deviation for both Universities and explain how you determined this.

Answers: 1

Show answers

Answers

Answer from: choiboiqg6811

The mean, median, and standard deviation of the University of Oregon are $451.33, $467.5, and $113.61 respectively.

The mean, median, and standard deviation of the University of Washington are $396.67, $380, and $56.27 respectively.

Step-by-step explanation:

We are given that a sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Oregon is: $295, $475, $345, $595, $538, $460.

A second sample of the amount of rent paid for one-bedroom apartments of similar size near the University of Washington is: $495, $422, $370, $333, $370, $390.

Firstly, we will calculate the mean, median, and standard deviation for the data of the University of Oregon.

Arranging the data in ascending order we get;

X = $295, $345, $460, $475, $538, $595.

The mean of the above data is given by the following formula;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{\$295+ \$345+ \$460+\$475+ \$538+\$595}{6}$

= $\frac{\$2708}{6}$ = $451.33

So, the mean price of rent near the University of Oregon is $451.33.

For calculating the median, we first have to observe that the number of observations (n) in the data is even or odd.

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}$

Here, the number of observations is even, i.e. n = 6.

So, Median = $\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}$

= $\frac{(\frac{6}{2} )^{th} \text{ obs. } + (\frac{6}{2}+1 )^{th} \text{ obs.}}{2}$

= $\frac{(3 )^{rd} \text{ obs. } + (4 )^{th} \text{ obs.}}{2}$

= $\frac{\$460 +\$475}{2}$ = $467.5

Hence, the median price of rent for the University of Oregon is $467.5.

Now, the standard deviation is calculated by using the following formula;

Standard deviation, S.D. = $\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }$

= $\sqrt{\frac{ (\$295 - \$451.33)^{2} +(\$345 - \$451.33)^{2} +......+(\$595 - \$451.33)^{2} }{6-1} }$

= $113.61

So, the standard deviation for the University of Oregon is $113.61.

Now, we will calculate the mean, median, and standard deviation for the data of the University of Washington.

Arranging the data in ascending order we get;

X = $333, $370, $370, $390, $422, $495.

The mean of the above data is given by the following formula;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{\$333+ \$370+ \$370+\$390+ \$422+\$495}{6}$

= $\frac{\$2380}{6}$ = $396.67

So, the mean price of rent near the University of Washington is $396.67.

For calculating the median, we first have to observe that the number of observations (n) in the data is even or odd.

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}$

Here, the number of observations is even, i.e. n = 6.

So, Median = $\frac{(\frac{n}{2} )^{th} \text{ obs. } + (\frac{n}{2}+1 )^{th} \text{ obs.}}{2}$

= $\frac{(\frac{6}{2} )^{th} \text{ obs. } + (\frac{6}{2}+1 )^{th} \text{ obs.}}{2}$

= $\frac{(3 )^{rd} \text{ obs. } + (4 )^{th} \text{ obs.}}{2}$

= $\frac{\$370 +\$390}{2}$ = $380

Hence, the median price of rent for the University of Washington is $380.

Now, the standard deviation is calculated by using the following formula;

Standard deviation, S.D. = $\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }$

= $\sqrt{\frac{ (\$333 - \$396.67)^{2} +(\$370 - \$396.67)^{2} +......+(\$495 - \$396.67)^{2} }{6-1} }$

= $56.27

So, the standard deviation for the University of Washington is $56.27.

Answer from: Quest

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

Poloma believes that the equation of the line of best fit for the following scatterplot is y=5/6x-31

Answer from: Quest

It is the top one. the answer is -7. that is smallest

Another question on Mathematics

Mathematics, 21.06.2019 22:30

60 musicians applied for a job at a music school. 14 of the musicians play both guitar and drums. what is the probability that the applicant who gets the job plays drums or guitar?

Answers: 1

Answer

Mathematics, 21.06.2019 22:30

What is the point of inflection for the function f(x)=2cos4x on the interval (0, pi/2)

Answers: 2

Answer

Mathematics, 21.06.2019 23:00

John has 1/2 pound of oranges to share with julie. if they share the oranges equally, how much will each of them have?

Answers: 1

Answer

Mathematics, 21.06.2019 23:40

Which point-slope form equation represents a line that passes through (3,-2) with a slope of -4/5