Looking for help finding the area to show work

  10. 60 in^2

  11. 27 cm^2

  12. 24 cm^2

  13. 4 in^2

  14. 24 cm^2

Step-by-step explanation:

The applicable formulas are ...

  trapezoid area: (1/2)(b1 +b2)h

  triangle area: (1/2)bh

  rectangle area: bh

  square area: s^2

where b, b1, b2 are base lengths, h is height, s is side length.

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Fill in the numbers and do the arithmetic.

10) A = (1/2)(10 +14)(5) = 60 . . . in^2

11) A = (1/2)(6 cm)(9 cm) = 27 cm^2

12) A = (8 cm)(3 cm) = 24 cm^2

13) A = (2 in)^2 = 4 in^2

14) A = (1/2)(9 +7)(3) = 24 . . . cm^2

3x^3-x^2+6x-9

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet