Quantos números de quatro algarismos distintos podemos formar com os algarismos 1, 2, 3, 4, 5 e 6? * 3 pontos
340
360
350
330

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).

Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).

Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).

Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

Step-by-step explanation:

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:)  <3

-I will also put it in spanish if you need it(Si quieres esta en espanol yo si sabes)

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

21

step-by-step explanation: