A zoo has a menagerie containing four pairs of different animals, one male and one female for each. The zookeeper wishes to feed the animals in a specific pattern: each time he feeds a single animal, the next one he feeds must be a different gender. If he starts by feeding the male giraffe, how many ways can he feed all the animals?

The zookeeper can feed all the animals in 144 ways

The number of different animals is given as:

The number of ways to feed any of the 4 male animals is:

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From the question, we understand that the female of the particular animal cannot be selected (yet).

So, there are 3 female animals left.

The number of ways to feed any of the 3 female animals is:

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So, the number (n) of ways to feed all the animals is:

Hence, he can feed all the animals in 144 ways

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144

Step-by-step explanation:

We will use permutations to solve this problem

There are 4 pairs each having a male and a female.

The total number of sample points is 4! = 4*3*2*1= 24

He chooses the male first  then the number of sample space he is left with are 3! = 3*2*1=6

The total number of ways he can select is 4! 3! = 24 * 6= 144

Another way of finding it out is

he has 4 pairs  each having a male and a female so he chooses 1st male then he would choose from this

4 female choices*3 male choices * 3 female choices *2 male choices *2 female choices *1 male choices *1 female choices *= 4*3*3*2*2*1*1= 144

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point