Please Answer Now Identify the function’s vertical asymptotes. h(x)=x-4/x^2-4 x = 2 x = 4 x = -2, x = 2 x = -4, x = 4

x = 2 and x = +2

Step-by-step explanation:

It's essential that you use parentheses to clarify what's happening here:

h(x)=x-4/x^2-4  =>  h(x)=(x-4) / (x^2-4)

We have vertical asymptotes at x values at which the denominator (x^2 - 4) is zero.  That would be x = 2 and x = +2.

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