NEED HELP ASAP PLEASE What would the equation of a hyperbola with directrices at x=±2 and foci at (6,0) (-6,0) be?

The equation of the hyperbola can be presented as follows;

Step-by-step explanation:

We have the equation of an hyperbola given as follows;

The foal length = a² + b² = c²

c = focal length

The directrix = a²/c

The focal point are (h + c, k) and (h - c, k)

Therefore, by comparison with the given focal points, (6, 0) and (-6, 0), we have;

k = 0 and h + c = 6, h - c = -6

Therefore;

6 - c - c = -6

-2·c = -12

c = 6

h = 0

a²/c = 2

a² = 2 × 6 = 12

a = 2·√3

12 + b² = 6²

b² = 6² - 12 = 24

b² = 24

b = 2·√6

The equation of the hyper bola can then be written as follows;

Which gives

x² - y² = 12

y² = x² - 12.

answer: the answer is b. i think hope i got it correct

step-by-step explanation:

write out the polynomial, with leading coefficient 1:

y = 1 (x+2)^1 (x-7)^1 (x-5)^2

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