An electronic company manufactures a specific component for a tuner amplifier. It finds that out of every 1,000 components produced, 8 are defectives. If the components are packed in boxes of 250, find a. the probability of 0,1,2 and 3 defectives in a box b. the probability that the box contains at least 3 defectives.

a. P(X = 0) = 0.134

P(X = 1) = 0.271

P(X = 2) = 0.272

P(X = 3) = 0.1812

b. P(X > 3) = 0.142

Step-by-step explanation:

The given parameters are

Number of defective component per 1000 = 8

Therefore, the probability that the specific component is defective = 8/1000 = 0.008

The binomial probability is given as follows;

The probability that the box contains at least 3 defectives is the probability P(X > 3) = 1 - (P(X = 3) +  P(X = 2) +  P(X = 1) +  P(X = 0))  

Which gives;

P(X > 3) = 1 - (0.1812 - 0.271 - 0.272 - 0.134) = 0.142

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.