11. What are the vertices of the ellipse whose equation is (x2)/9 + (y2)/4 = 1? please show the work

I think that this is the answer

standard form of equation for ellipse with vertical major axis (a^2 under y^2):

(x-h)^2/b^2+(y-k)^2/a^2=1,a>b, (h,k) being the (x,y) coordinates of the center.

For given equation: x^2/9+y^2/36=1

center: (0,0)

a^2=36

a=√36=6

length of vertical major axis=2a=12

Vertices are end points of major axis=(0,0�a)=(0,0�6)=(0,-6) and (0,6)

Vertices are at (0,-6) and (0,6)

Step-by-step explanation:

15 units use socratic

step-by-step explanation: 15 units

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.