Please answer this ASAP. The question is down below. Thank you!

Step-by-step explanation:

Well we can start by seeing if the parabola is the same width by comparing it to its parent function ( y = x^2 )

In y = x^2 the 2nd lowest point is just up 1 and right 1 away from the vertex.

This is not true for our parabola.

So we can widen it by to the desidered width by making the x^2 into a .5x^2.

So far we’ve got y = .5x^2

Now the parabola y intercept is at -5.

So we can add a -5 into the equation making it.

y = .5x^2 - 5

Now for the x value.

So we can find the x value by seeing how far away the parabola is from from the y axis.

So the x value is -2x.

So the full equation is

Look at the image below to compare.

               Transformations: vertical shrink by a factor of 1/2,

                                            horizontal shift 2 units to the right,

                                            vertical shift 7 units down.

Step-by-step explanation:

Vertex form: y = a(x - h)² + k

Standard form: y = ax² + bx + c

Given: Vertex (h, k) = (2, -7), the y-intercept (0, c) = (0, -5)

Input those values into the Vertex form to solve for the a-value

-5=a(0 - 2)² - 7

2 = a(- 2)²

2 = 4a

a) Input a = 1/2 and (h, k) = (2, -7) into the Vertex form

b) You can plug in a = 1/2, c = -5, (x, y) = (2, -7) to solve for "b"

    or

   You can expand the Vertex form (which is what I am going to do):

c) Use the Vertex form to describe the transformations as follows:

a = 1/2  --> vertical shrink by a factor of 1/2

h = 2    --> horizontal shift 2 units to the right

k = -7   --> vertical shift 7 units down

you forgot an image

step-by-step explanation: