Rhombus $ABCD$ has perimeter $148$, and one of its diagonals has length $24$. What is the area of $ABCD$?

Area of the rhombus=840

Step-by-step explanation:

Perimeter of a rhombus=4a

148=4a

a=148/4

=37

a=37

The diagonal divides the rhombus into two congruent triangle,

Each congruent triangle= 37 x 37 x 24.

To get the area of the rhombus, we will find the area of one of the congruent triangle, then multiply by 2.

Using Hero's formula to find the area of a triangle, we will use the three sides

Area = √[ s(s-a)(s-b)(s-c) ]

where a, b, and c are the lengths of the three sides: a = 37, b = 37, and c = 24.

s=semiperimeter

s = (a + b + c) / 2

= (37 + 37 + 24)/2

= 98/2

= 49.

s=49

Substitute all the values into the formula

Area = √[ s(s-a)(s-b)(s-c) ]

= √[ 49(49-37)(49-37)(49-24) ]

=√[ 49(12)(12)(25) ]

=√[49(3600)]

=√(176,400)

= 420

Area of one triangle=420

Area of a rhombus=Area of one triangle×2

=420×2

=840

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

6 meters

step-by-step explanation: